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AR521 - Printable Version +- How2pass.com Forums (https://www.how2pass.com/forum) +-- Forum: CCNP (https://www.how2pass.com/forum/forum-6.html) +--- Forum: CCNP ENARSI 300-410 Forum (https://www.how2pass.com/forum/forum-15.html) +--- Thread: AR521 (/thread-2534.html) |
AR521 - chewosaurus - 08-18-2025 Not sure if this question is correct, that being said I'm not exactly an expert on the topic. Correct answer as it stands is the answer with the K values as 0 1 1 1 0 0 But why? what's the reason for this answer, I've researched as much as I can but I still don't get why this answer was chosen to be correct. The only answer that I can see possibly being correct is the answer with the K values 0 1 0 1 0 0 The reason why this could be correct is because this is Cisco's default values, and if the EIGRP neighborship is down due to mismatch in K values, surely the default would be a better option here? Other than that, if you believe the current answer to be correct please enlighten me. Thanks. RE: AR521 - help_desk - 08-19-2025 In EIGRP, two routers will only form a neighbor adjacency if their K-values (metric weights) match. The K-values correspond to the metric calculation formula and must be identical across all peers in the same EIGRP AS. By default, Cisco uses the values "0 1 0 1 0 0" but none of the options are using these k-values. Hence, we choose which fits best. When we configure metric weights, the first value is TOS which is always 0. Which means only two options remain. K5 must be 0 unless K4 > 0, otherwise the reliability term can be rejected. Many IOS versions reject such combination. This leaves us with only one correct combination "metric weights 0 1 1 1 0 0". Although these aren't default values but are the only ones correct. |