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QID: AN437 and AN491
#1
QID AN437

posted answer : ipv6 address fc00:0000:aaaa:a15d:1234:2343:8aca/64
Why correct answer has only 28 hex-digits, not 32 hex-digits  ?  I do not see :: in this answer

QID AN491 

IMO correct answer should be : ip domain-name domain ...since the question asks for command BEFORE entering the command to generate RSA key
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#2
Thank you for your feedback. Both questions have been fixed.
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#3
when was the test last updated on H2P site ?
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#4
(10-07-2022, 12:10 AM)ejohnson7 Wrote: when was the test last updated on H2P site ?

Last Updated: October 04, 2022
https://www.how2pass.com/ccna-200-301-pr...stions.php
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#5
Can someone please help understand the answers to this question?  

172.16.2.128=>255.255.255.128
172.16.3.64  =>255.255.255.224
172.16.3.128=>255.255.255.240
172.16.3.192=>255.255.255.248
172.16.4.0   =>255.255.254.0

Am I making this too hard for myself?  I just don't get it.

Please advise

Thanks
dglorioso
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#6
(11-15-2022, 06:01 PM)darrenglorioso Wrote: 172.16.2.128=>255.255.255.128  = block of 128 IP's (126+2)
172.16.3.64  =>255.255.255.224 = block of 32 IP's (30+2)
172.16.3.128=>255.255.255.240  = block of 16 IP's (14+2)
172.16.3.192=>255.255.255.248  = block of 8 IP's (6+2)
172.16.4.0  =>255.255.254.0       = block of 512 IP's (510+2)

+2 in each block represent ==> NetworkID and BroadcastID

I do not see a copy of the question but I assume that you
have to assign a block of IP's to fulfil specific request.

Google search: IP CALCULATOR    that will provide additional info about each block/subnet
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