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havenlad

192.168.20.24 /29 - default gateway is what?

the network is incremented by 8 so we are in the 192.168.20.24 - 31 range

The answer says the default gateway is .25.  Surely that should be 24?
The given explanation is clear enough but here I try again:

Please note that multiples of the increment 8 are subnet IDs, i.e. they are network addresses or subnet addresses and you cannot use them as host addresses.

subnet mask = /29 = 255.255.255.248
subnet increment = 256 - 248 = 8

Therefore, subnet IDs are in multiples of 8.
Here subnet ID: 192.168.20.24/29
Subnet host address range: 192.168.20.25 - 192.168.20.30
Broadcast address: 192.168.20.31

So the first usable host address is 192.168.20.25 = default gateway address.

havenlad

Thanks yes that does make sense.  For some reason I was trying to use the network number as the default gateway - sorry to waste your time