QID:N64 wrong answers? - Printable Version +- How2pass.com Forums (https://www.how2pass.com/forum) +-- Forum: CCNA (https://www.how2pass.com/forum/forum-4.html) +--- Forum: Answer this question (https://www.how2pass.com/forum/forum-11.html) +--- Thread: QID:N64 wrong answers? (/thread-735.html) |
QID:N64 wrong answers? - havenlad - 10-09-2012 192.168.20.24 /29 - default gateway is what? the network is incremented by 8 so we are in the 192.168.20.24 - 31 range The answer says the default gateway is .25. Surely that should be 24? Re: QID:N64 wrong answers? - forumsupport - 10-12-2012 The given explanation is clear enough but here I try again: Please note that multiples of the increment 8 are subnet IDs, i.e. they are network addresses or subnet addresses and you cannot use them as host addresses. subnet mask = /29 = 255.255.255.248 subnet increment = 256 - 248 = 8 Therefore, subnet IDs are in multiples of 8. Here subnet ID: 192.168.20.24/29 Subnet host address range: 192.168.20.25 - 192.168.20.30 Broadcast address: 192.168.20.31 So the first usable host address is 192.168.20.25 = default gateway address. Re: QID:N64 wrong answers? - havenlad - 10-12-2012 Thanks yes that does make sense. For some reason I was trying to use the network number as the default gateway - sorry to waste your time |