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QID:RTE101 typo perhaps?
#2
The answer is correct.
You need the following interfaces in AREA 0
Rtr C == E0/0 and E0/1
Rtr A == E0/0 and E0/1
Rtr B == E0/0 and E0/1

Now on Rtr A, E1/0 will be in area 1
On Rtr B, E1/0 will be in area 2

Based on the Exhibit::
Area 0 resides inside the Triangle setup between C, A, and B
Since all interfaces on Rtr C are in Area 0, you need interfaces on Rtr A and B with which to talk with.
Those being E0/0 on both.
You also need the interfaces between A and B to be in the same area....now they could be Area 1, Area 0 or Area 2, or even Area 54 if you like....
But from the debug log we are given it is clear that on RouterA, a packet from IP Address 10.3.0.2 (which is Rtr B) was received.
Router A has been configured with Area 1 on this interface, and got a packet reflecting Area 2....so there is a mismatch.
Based on the diagram and getting OSPF to work in the easiest possible way, the best thing would be to just configure Area 0 on that network.

Also from the standpoint of redundancy, you will want the link between A and B to be in Area 0.
So if perhaps the link between Rtr A and Rtr C fails, there is still a path to Rtr C going through Rtr B.
For Example, if the link between Rtr A and B were configured as Area 2....then traffic from Area 1 would never get to the backbone, Area 0.
Because all areas have to have a connection to Area 0....that is how different areas talk w/ each other.  So if the link failed...the Area 1 traffic would not use Area 2 as a transit area...unless you created a virtual-link.
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Messages In This Thread
QID:RTE101 typo perhaps? - by DriveOn - 06-04-2011, 04:27 PM
Re: QID:RTE101 typo perhaps? - by sdunn96 - 06-06-2011, 12:58 PM
Re: QID:RTE101 typo perhaps? - by DriveOn - 06-21-2011, 08:47 PM

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