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QID: AN437 and AN491
#6
(11-15-2022, 06:01 PM)darrenglorioso Wrote: 172.16.2.128=>255.255.255.128  = block of 128 IP's (126+2)
172.16.3.64  =>255.255.255.224 = block of 32 IP's (30+2)
172.16.3.128=>255.255.255.240  = block of 16 IP's (14+2)
172.16.3.192=>255.255.255.248  = block of 8 IP's (6+2)
172.16.4.0  =>255.255.254.0       = block of 512 IP's (510+2)

+2 in each block represent ==> NetworkID and BroadcastID

I do not see a copy of the question but I assume that you
have to assign a block of IP's to fulfil specific request.

Google search: IP CALCULATOR    that will provide additional info about each block/subnet
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Messages In This Thread
QID: AN437 and AN491 - by slawekstec - 09-27-2022, 12:51 PM
RE: QID: AN437 and AN491 - by forumsupport - 10-04-2022, 11:23 AM
RE: QID: AN437 and AN491 - by ejohnson7 - 10-07-2022, 12:10 AM
RE: QID: AN437 and AN491 - by forumsupport - 10-10-2022, 09:40 AM
RE: QID: AND49 - by darrenglorioso - 11-15-2022, 06:01 PM
RE: QID: AND49 - by slawekstec - 11-15-2022, 09:21 PM
RE: QID: AN437 and AN491 - by serbet - 12-20-2022, 06:22 PM
RE: QID: AN437 and AN491 - by forumsupport - 12-21-2022, 04:43 PM

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